Experiment of tiratic oxilic acid wih mass 4,5g and volume of 25ml,nd concentration of 0,05mol.dm.3 against volume of 14ml and 1,79mol.dm3 sodium hydoxide to determine the concentration of sodium hydroxide,,

To determine the concentration of sodium hydroxide (NaOH) using an experiment with oxalic acid (H2C2O4), you will need to use a balanced chemical equation.

The balanced chemical equation for the reaction between oxalic acid and sodium hydroxide is:
2H2C2O4 + 2NaOH -> Na2C2O4 + 2H2O

Given the following information:
Mass of oxalic acid (H2C2O4) = 4.5g
Volume of oxalic acid solution = 25ml
Concentration of oxalic acid solution = 0.05mol.dm^-3
Volume of sodium hydroxide (NaOH) solution = 14ml
Concentration of sodium hydroxide (NaOH) solution = 1.79mol.dm^-3

Step 1: Convert the volume of oxalic acid solution to liters:
Volume of oxalic acid solution = 25ml = 25/1000 = 0.025L

Step 2: Calculate the number of moles of oxalic acid:
Number of moles = concentration × volume
Number of moles of oxalic acid = 0.05mol.dm^-3 × 0.025L = 0.00125mol

Step 3: Use the balanced chemical equation to determine the stoichiometry between oxalic acid and sodium hydroxide. From the balanced equation, we can see that 2 moles of oxalic acid react with 2 moles of sodium hydroxide.

Step 4: Convert the number of moles of oxalic acid to the number of moles of sodium hydroxide:
Since the molar ratio of oxalic acid to sodium hydroxide is 1:1, the number of moles of sodium hydroxide is also 0.00125mol.

Step 5: Calculate the concentration of sodium hydroxide:
Concentration of sodium hydroxide = number of moles/volume
Concentration of sodium hydroxide = 0.00125mol/0.014L = 0.0893mol.dm^-3

Therefore, the concentration of sodium hydroxide is 0.0893mol.dm^-3.