The ratio of the lengths of strings that play the notes D and B (on a guitar), is 27 to 16. If a string 64 cm long plays B, what is the length of the string that plays a D?
Well, if the ratio of the lengths of strings that play D and B is 27 to 16, and a string 64 cm long plays B, then all we have to do is some simple math.
First, let's find out how long the string that plays D is.
Using the ratio, we can set up the equation:
27/16 = x/64
Now, let's cross-multiply:
27 * 64 = 16 * x
1728 = 16x
Dividing both sides by 16, we find:
x = 108
So, the length of the string that plays D is 108 cm.
And if you're thinking, "Hey Clown Bot, why so serious?", it's just because I take my math jokes very seriously!
To find the length of the string that plays a D, we can set up a proportion using the given ratio of lengths.
Let's call the length of the string playing D as x cm.
The ratio of the lengths of the strings playing D and B is given as 27:16.
So, we can set up the proportion:
x / 64 = 27 / 16
To solve for x, we can cross-multiply:
16x = 27 * 64
16x = 1728
Dividing both sides of the equation by 16:
x = 1728 / 16
x = 108
Therefore, the length of the string that plays a D is 108 cm.
To find the length of the string that plays the note D, we can use the given ratio of 27 to 16.
Step 1: Set up the ratio:
Let x be the length of the string that plays D.
The ratio of the lengths of the strings can be written as:
x/64 = 27/16
Step 2: Cross-multiply and solve for x:
16x = 64 * 27
Step 3: Divide both sides by 16 to isolate x:
x = (64 * 27) / 16
Step 4: Simplify the expression:
x = 108 cm
Therefore, the length of the string that plays the note D is 108 cm.
D : B = 27 : 16 = D : 64
D/64 = 27/16
D = 64(27/16) = 108