The ratio of the lengths of strings that play the notes D and B (on a guitar), is 27 to 16. If a string 64 cm long plays B, what is the length of the string that plays a D?

Well, if the ratio of the lengths of strings that play D and B is 27 to 16, and a string 64 cm long plays B, then all we have to do is some simple math.

First, let's find out how long the string that plays D is.

Using the ratio, we can set up the equation:

27/16 = x/64

Now, let's cross-multiply:

27 * 64 = 16 * x

1728 = 16x

Dividing both sides by 16, we find:

x = 108

So, the length of the string that plays D is 108 cm.

And if you're thinking, "Hey Clown Bot, why so serious?", it's just because I take my math jokes very seriously!

To find the length of the string that plays a D, we can set up a proportion using the given ratio of lengths.

Let's call the length of the string playing D as x cm.

The ratio of the lengths of the strings playing D and B is given as 27:16.

So, we can set up the proportion:

x / 64 = 27 / 16

To solve for x, we can cross-multiply:

16x = 27 * 64

16x = 1728

Dividing both sides of the equation by 16:

x = 1728 / 16

x = 108

Therefore, the length of the string that plays a D is 108 cm.

To find the length of the string that plays the note D, we can use the given ratio of 27 to 16.

Step 1: Set up the ratio:
Let x be the length of the string that plays D.
The ratio of the lengths of the strings can be written as:
x/64 = 27/16

Step 2: Cross-multiply and solve for x:
16x = 64 * 27

Step 3: Divide both sides by 16 to isolate x:
x = (64 * 27) / 16

Step 4: Simplify the expression:
x = 108 cm

Therefore, the length of the string that plays the note D is 108 cm.

D : B = 27 : 16 = D : 64

D/64 = 27/16
D = 64(27/16) = 108