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Find derivative using logarithmic differentiation
F(x)= secx^cotx

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asked by Sarah
  1. f = secx^cotx
    log f = cotx * log secx
    1/f f' = (-csc^2 x * log secx) + (cotx * secx*tanx/secx)
    f' = secx^cotx (1 - csc^2(x) log secx)

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    posted by Steve

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