physics

a mass is thrown vertically upwards with an initial velocity of 30m/s. a second mass is dropped 0.5s later from directly above the height of 60m from the mass. when do they meet and at what height?

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asked by adii
  1. first object:
    hf=30t-4.9t^2
    second object:
    hf=60-4.9(t-.5)^2

    since they meet at hf, set them equal, solve for tf.

    for height, put that tf back into either equation, solve for tf.

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