Math

2 sides of a triangle are consecutive odd integers. The third side is twice as long as the shortest side. The perimeter is 22. Find the length of the shortest side.

I guessed
A+b+c=22 and that's as far as I got

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  1. You were right as far as you went. But, you didn't use the rest of the information they gave you.

    a+b+c = 22

    But what else do we know?
    If a is the short side (assuming it is indeed an odd integer), then

    b=a+2 (next odd integer)
    c=2a (twice as big)

    So, substituting in the given information,

    a+b+c = 22
    a + a+2 + 2a = 22
    4a+2 = 22
    4a = 20
    a = 5

    So, the sides are 5,7,10

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    posted by Steve

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