A body is to be projected at an angle with a velocity 24m/s just to pass over an obstacle 14m high at adistance of24m.then angle is what.

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  1. Do the vertical problem first
    Vi = initial speed up
    v = Vi - g t
    at top, v = 0
    0 = Vi - g t
    Vi = g t
    t = Vi/g

    h = 0 + Vi t - .5 g t^2
    14 = Vi^2/g - .5 Vi^2/g
    28 g = Vi^2
    Vi = sqrt (28 g)
    Vi = 16.6 m/s

    Vi = v sin theta
    16.6 = 24 sin theta
    so ....

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    posted by Damon

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