A motorist is driving at a constant velocity of 28 m/s when he decides to pass a
car that is in front of him. He accelerates at a rate of 2.5 m/s2 for 3.0 seconds
while passing the car. What is his velocity at the end of the 3.0 seconds?
This is similar to the question you posted before, assuming that you are the same anonymous.
Use v=u+ at once again. (Take 28 as your initial velocity.)
To find the final velocity of the motorist at the end of the 3.0 seconds, we can use the equation of motion:
v = u + at
Where:
v = final velocity
u = initial velocity
a = acceleration
t = time
In this case, the initial velocity (u) is 28 m/s, the acceleration (a) is 2.5 m/s^2, and the time (t) is 3.0 seconds.
Now, substitute the given values into the equation:
v = 28 m/s + (2.5 m/s^2)(3.0 s)
First, calculate the product of acceleration and time:
(2.5 m/s^2)(3.0 s) = 7.5 m/s
Now, substitute the calculated acceleration into the equation:
v = 28 m/s + 7.5 m/s
Add the velocities:
v = 35.5 m/s
Therefore, the motorist's velocity at the end of the 3.0 seconds is 35.5 m/s.