math

the polynomials P(x)= kx^3+3x^2-3 and Q(x)= 2x^3-5x+k when divided by (x-4) leave the same remainder the value of k is

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asked by kabhir
  1. p(4) = 64k + 48 - 3
    = 64k + 45

    Q(4) = 128 - 20 + k
    = k + 108

    by the remainder theorem , each of these are the remainders when divided by x-4
    But they are equal ...
    64k + 45 = k + 108
    63k = 63
    k = 1

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    posted by Reiny

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