algebra

the one to one function g and h
g={(-4,5),(2,-5),(3,2),(4,9)
h(x)= 2x+9
find the following
g^-1(2)=
h^1(x)=
(h*h^1)(-7)

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1. since g(3) = 2, g^-1(2) = 3
since h(-4) = 1, h^-1(1) = -4
(h*h^-1)(-7) = h(7)*h^-1(-7) = (-5)*(-8) = 40

If you meant (h◦h^-1)(-7) then that would be -7, since by definition (h◦h^-1)(x) = x.

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posted by Steve

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