Calculus

Assume v(t) = 6t - 18 on the interval [0, 6]. Find the total distance that the object traveled on [0, 6].

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  3. 👁 97
asked by Jamie
  1. we just did one of these

    x(t) = 3t^2 - 18t + c

    Now just figure x(6)-x(0)

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    posted by Steve
  2. I got 0. That doesn't make sense to me...

    x(0) = 3(0)^2 - 18(0) + C = 0+C
    x(6) = 3(6)^2 - 18(6) + C = 108-108+C = 0+C
    x(6)-x(0)=0

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    posted by Jamie
  3. Your velocity is zero at t = 3 !!!!!
    right in the middle of your range.
    It reversed direction midstream
    You calulated displacement (where it moved to which was nowhere)
    instead of how far it went (distance moved)
    do t = 0 to t = 3
    then t = 3 to t = 6
    add the ABSOLUTE VALUES

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    posted by Damon
  4. See Baggins, Bilbo, "There and Back Again".

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    posted by Damon
  5. So is the total distance 54?

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    posted by Jamie
  6. yes

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    posted by Damon

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