chemistry

How would you do this question:

A student dissolved 5.0 g of vitamin C in
250 mL of water. The molar mass of ascorbic acid is 176 g/mol, and its Ka is 8.0 × 10−5. Calculate the pH of the solution. Note: Abbreviate the formula of ascorbic acid to HAsc.

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asked by Q
  1. mols HAsc = 5/molar mass = approx 0.03 but you need to do it more accurately.

    ........HAsc ==> H^+ + Asc^-
    I......0.03......0......0
    C.......-x.......x.......x
    E......0.03-x....x......x

    Substitute the E line into Ka expression for HAsc and solve for x, then convert to pH.

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    posted by DrBob222

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