college physics

A horizontal spring with a spring constant k = 322 N/m is uncompressed from a length of 1.4 cm back to its unstretched length. Calculate the change in potential energy in Joules to 2 s.f.

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asked by wes
  1. Lack of better data, assume the 1.4 cm is the difference between stretched and unstretched length.

    Work done = Δpotential energy
    = (1/2)k(Δx)²

    First change everything to SI units then the result will be in joules.

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    posted by MathMate

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