How much of a stock (18.5 M) HCl solution would be required to make 100mL of 0.025 M HCl?
you want to dilute it 18.5/.025 times or 740 times. That means, 1 part stock, 739 parts water. What is one part? 100ml/740= .135ml
That will be tough to measure.
To determine how much of a stock 18.5 M HCl solution is required to make 100 mL of 0.025 M HCl, we can use the equation for dilution:
C₁V₁ = C₂V₂
Where:
C₁ = Initial concentration of the stock solution
V₁ = Volume of the stock solution used
C₂ = Final concentration of the diluted solution
V₂ = Final volume of the diluted solution
In this case:
C₁ = 18.5 M (concentration of the stock HCl solution)
V₁ = ?
C₂ = 0.025 M (desired concentration of the diluted HCl solution)
V₂ = 100 mL (desired volume of the diluted HCl solution)
Rearranging the equation, we have:
V₁ = (C₂ × V₂) / C₁
Plugging in the values:
V₁ = (0.025 M × 100 mL) / 18.5 M
Calculating the equation:
V₁ = 0.1351 mL
Therefore, approximately 0.1351 mL of the stock 18.5 M HCl solution would be required to make 100 mL of 0.025 M HCl.