electronics

Using wheatstone bridge where R1=top left R2=top right R3=bottom left RT(thermistor 2.11spec)=bottom right.
R1=2.2kohm
R3=8.2Kohm.
must have 0 output at 0degC
calculate the required value of R2.

Thermistor specs:
resistance @
20degC=2K
25degC=1.68K
200degC=37ohm

min operating resistance
37ohm

Characteristic temp b:
25-85degC nominal 3050K+/-5%

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asked by jerome
  1. Rt = R2*R3/R1 = 2.11k
    R2*8.2k/2.2k = 2.11k
    3.727R2 = 2.11k
    R2 = 0.566k = 566 ohms.

    NOTE: I'm assuming that Rt = 2.11k at
    0oC.

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    posted by Henry

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