Could you explain to me why 9/64 is the answer to the following questions:A fair spinner is spun three times. The spinner is labeled A,B,C,D. What is the probability of getting a c exactly twice?
because 9/64=3/16 (9/64)/3=3/16
three spins, four possible answers per spin. 3*4=16.
prob(c) = 1/4
prob(not c) = 3/4
so you are looking for
c c notc = (1/4)(1/4)(3/4) = 3/64
c notc c = (1/4)(3/4)(1/4) = 3/64
notc c c = (3/4)(1/4)(1/4) = 3/64
prob of your event = 3(3/64) = 9/64
Dera mom i love you so much do you love me
To find the probability of getting a specific outcome, such as C appearing twice when a spinner is spun three times, we need to determine the total number of possible outcomes and the number of favorable outcomes.
In this case, the spinner has four labels: A, B, C, and D. Therefore, each spin has four possible outcomes. Since we are spinning the spinner three times, the total number of possible outcomes can be calculated as 4 multiplied by 4 multiplied by 4, which equals 64.
Now, let's determine the number of favorable outcomes. We want C to appear twice in the three spins. We can have C in any two of the three spins, so we need to determine the number of ways we can choose two out of the three spins for C to appear.
This can be done using combinations. The number of combinations to choose two items from a set of three can be calculated as 3! / (2!(3 - 2)!), where "!" denotes the factorial function. Simplifying this, we have 3! / (2!1!). This becomes (3 * 2 * 1) / (2 * 1 * 1) = 3.
Therefore, there are three possible combinations of two spins out of three where C appears twice. For example, if we label the spins as Spin 1, Spin 2, and Spin 3, the three combinations would be: (Spin 1, Spin 2), (Spin 1, Spin 3), and (Spin 2, Spin 3).
Now, we can calculate the probability by dividing the number of favorable outcomes (3) by the total number of possible outcomes (64): 3/64, which simplifies to 9/64.
Hence, the probability of getting C exactly twice when spinning the fair spinner three times is 9/64.