At equilibrium, what is the hydrogen-ion concentration if the acid dissociation constant is 0.000 001 and the acid concentration is 0.01M?

can you help me step by step and explain?

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asked by Angela
  1. ...........HA --> H^+ + A^-

    Ka = 1E-6 = (H^+)(A^-)/(HA)
    Substitute the E line into Ka expression and solve for x = (H^+).

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    posted by DrBob222
  2. acid(aq)>>H+ ??




    x= (-E-6+-(1E-12 +4E-8)/2

    x= you work it out, about
    = -.5E-6+1E-4 about .000095

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