Is the molecular geometry around the carbon atom(s)

trans-1,2 difluroethylene a trigonal planar?

I'm pretty sure it is, but I just need to varify it, if it is not a trigonal planar what is the molecular geometry around the carbon atom(s)?

Trigonal planar around each C atom. The C atoms are co-planar.

To determine the molecular geometry around the carbon atom(s) in trans-1,2-difluoroethylene, we first need to draw the Lewis structure of the molecule.

The molecular formula for trans-1,2-difluoroethylene is C2H2F2.

Now, let's draw the Lewis structure:

C = C
| |
F F

In this structure, each carbon atom is bonded to two other atoms (one hydrogen and one fluorine).

To determine the molecular geometry, we need to consider the electron groups around the carbon atom(s). In this case, each carbon atom has three electron groups - the two sigma bonds and the lone pair of electrons on the carbon.

Based on the VSEPR (Valence Shell Electron Pair Repulsion) theory, when a molecule has three electron groups around a central atom, the electron groups will arrange themselves in a trigonal planar geometry.

Therefore, the molecular geometry around the carbon atom(s) in trans-1,2-difluoroethylene is indeed trigonal planar.