if+all+nitrogen+atoms+from+.1+mole+No2+and+.2+N2o4+are+removed+then+how+many+moles+of+n2+can+be+prepared+from+it
See your other post above.
To determine the number of moles of N2 that can be prepared from the given amount of nitrogen atoms, we first need to calculate the moles of nitrogen atoms present in 0.1 mole of NO2 and 0.2 mole of N2O4.
NO2 consists of one nitrogen atom per molecule, so 0.1 mole of NO2 contains 0.1 mole of nitrogen atoms.
N2O4 consists of two nitrogen atoms per molecule, so 0.2 mole of N2O4 contains 2 * 0.2 = 0.4 mole of nitrogen atoms.
Now that we have the total moles of nitrogen atoms from both compounds, we can determine the maximum number of moles of N2 that can be prepared. N2 is formed by the combination of two nitrogen atoms.
For every 2 moles of nitrogen atoms, we can obtain 1 mole of N2. Therefore, we divide the total moles of nitrogen atoms by 2 to get the moles of N2.
For the given amounts of NO2 and N2O4:
Moles of N2 = (Moles of nitrogen atoms from NO2 + Moles of nitrogen atoms from N2O4) / 2
= (0.1 + 0.4) / 2
= 0.5 / 2
= 0.25 mole of N2
Hence, 0.25 mole of N2 can be prepared from the given quantities of NO2 and N2O4.