# physics

During the Olympic ice competition, Boris (m = 75 kg) glides at 1.8 m/s to a stationary Juliette (52 kg) and hangs on. How far will the pair slide after the collision if the coefficient of kinetic friction between the ice and their skates is .042?

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1. get V from momentum

(75 + 52) V = 75 (1.8)

calculate V

calculate (1/2) m V^2

friction force = .042 * m * g

friction force * distance = (1/2) m V^2
or actually m cancels
.042 g d = .5 V^2

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posted by Damon

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