Physics

A football player punts the ball at a 45.0o
angle. Without an effect from the wind, the ball would
travel 60.0 m horizontally. (a) What is the initial speed of the ball? (b) When the ball is near its
maximum height it experiences a brief gust of wind that reduces its horizontal velocity by
1.50 m/s. What total distance does the ball travel horizontally?

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  1. without wind:

    hf=hi+vo*t-1/2 g t^2
    hf, hi =0
    time t= sqrt(2vSin45)/g)
    distance horizontal=vo*cos45*t
    60=vo*.707*sqrt(2vo*.707/9.8)
    solve for vo.

    Then, the wind gust: time in the air is the same, so distance=t/2*vo .707+t/2(vo*.707-1.5)

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    bobpursley
  2. 4.78

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