Calculus

Find the point where the tangent to the curve is horizontal.

f(x) = (x^2-2x+4)/(x^2+4)

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  1. That would be there the derivative
    f'(x) = 0

    The derivative is
    f'(x) = (x^2+4)(2x -2) - (x^2-2x+4)(2x)]/(x^2 +4)^2

    Set the numerator = 0 and solve for x.

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