physics

A 55 kg skateboarder accelerates down a ramp and hits the pavement moving at 5.6 m/s. If the pavement has a coefficient of friction of 0.11, how far will skateboarder glide before coming to a stop?

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asked by grey
  1. normal force = 55 g
    friction force = .11 * 55 g

    acceleration = F/m = -.11 * 55 * g /55
    = -.11 g = -1.08 m/s^2

    v = Vi + a t
    0 = 5.6 - 1.08 t
    t = 5.2 seconds to stop
    go at average speed (5.6 /2) for 5.2 seconds
    d = 14.5 meters

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    posted by Damon

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