A sample of helium has a volume of 235 ml and a pressure of 565 mm Hg. What will be the pressure if the helium is compressed to 215 mL (T constant)
PV = n R T = constant
so
P1 V1 = P2 V2
565 (235) = P2 (215)
To calculate the final pressure of the compressed helium, we can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional when temperature is held constant.
Boyle's Law equation: P₁V₁ = P₂V₂
Where:
P₁ = initial pressure
V₁ = initial volume
P₂ = final pressure (what we want to find)
V₂ = final volume
Given information:
P₁ = 565 mm Hg
V₁ = 235 mL
V₂ = 215 mL
Now, let's plug in the values into the equation and solve for P₂:
P₁V₁ = P₂V₂
565 mm Hg * 235 mL = P₂ * 215 mL
132775 mm Hg * mL = P₂ * 215 mL
Divide both sides of the equation by 215 mL:
P₂ = (132775 mm Hg * mL) / 215 mL
P₂ ≈ 618.02 mm Hg
Therefore, the final pressure of the compressed helium, at a volume of 215 mL and constant temperature, will be approximately 618.02 mm Hg.