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An object is thrown up with a velocity 30m/s. If the acceleration due to gravity is 10m/s2. Cal. I) its velocity after 2s. II) the maximum height reaches. III) the time taken for the take object to come to rest.

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asked by George
  1. 1. V = Vo + g*t = 30 - 10*2 = 10 m/s.

    2. hmax = (V^2-Vo^2)/2g
    hmax = (0-(30)^2)/-20 =

    3. V = Vo + g*Tr = 0 @ hmax.
    Tr = -Vo/g = -30/-10 = 3 s. = Rise time.

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    posted by Henry

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