# math -logarithm

Write the equations in logarithmic form.
(a)
729 = 93(9 to the 3rd power)

(b)
25 = 1/5 −2( 1/5 to the -2 power)

a = bc ( c squared)

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1. 729=9³
log9729 = 3

25 = (1/5)-2
log(1/5)25 = -2

for a=bc²
rearrange to
(a/b) = c²
and proceed similar to above.

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posted by MathMate

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