In a random survey, 8 out of 18 students Would rather go to an amusement park than to the zoo. In a group of 225 students, how many students can you expect to prefer the amusement park?
prob(going to amusement park) = 8/18 = 4/9
so number of the 225 who would go
= (4/9)(225) = 100
notice Ms Sue's equation will yield the same answer.
To find out how many students you can expect to prefer the amusement park out of a group of 225 students, you can use proportions.
First, find the proportion of students who prefer the amusement park based on the random survey. In the survey, 8 out of 18 students preferred the amusement park. Therefore, the proportion of students who prefer the amusement park is 8/18.
Next, use this proportion to calculate the expected number of students who prefer the amusement park out of a group of 225 students. Multiply the proportion (8/18) by the total number of students in the group (225).
Expected number of students who prefer amusement park = (8/18) * 225
Simplifying this equation:
Expected number of students who prefer amusement park ≈ 8 * 12.5
Expected number of students who prefer amusement park ≈ 100
Therefore, you can expect approximately 100 students out of a group of 225 students to prefer the amusement park.
Do you divide?
Reiny can you help me?
Mrs. Sue
8/18 = x/225
Cross multiply and solve for x.