Physics

A car drives off a 20 m bridge at 35 m/s. Find the distance from the base of the bridge to when the car will land. (2 part question)

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asked by Jamika
  1. Assuming it is a 20 m bridge.

    Initial vertical velocity = 0
    time to reach base = t
    then
    t=√(-2Δy/g)
    =√(2*20/9.8)
    =2.02 s
    Horizontal distance
    =2.02*35 m/s
    =70.7 m approximately

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    posted by MathMate

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