A car drives off a 20 m bridge at 35 m/s. Find the distance from the base of the bridge to when the car will land. (2 part question)
Assuming it is a 20 m bridge.
Initial vertical velocity = 0
time to reach base = t
then
t=√(-2Δy/g)
=√(2*20/9.8)
=2.02 s
Horizontal distance
=2.02*35 m/s
=70.7 m approximately