# Physics

A car drives off a 20 m bridge at 35 m/s. Find the distance from the base of the bridge to when the car will land. (2 part question)

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1. Assuming it is a 20 m bridge.

Initial vertical velocity = 0
time to reach base = t
then
t=√(-2Δy/g)
=√(2*20/9.8)
=2.02 s
Horizontal distance
=2.02*35 m/s
=70.7 m approximately

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posted by MathMate

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