Find an equation of the line that passes through two points.

(0,4) and (7,10)

the slope of the line is ∆y/∆x, so

m = 6/7

Now you have a point and a slope, so the line is

y-4 = 6/7 (x-0)
or
y-10 = 6/7(x-7)

and you can massage them to whatever form you like, and convince yourself that they are really the same equation.

After12 years I shall be 3 times as old as I was 4 years ago find my present age

To find the equation of a line that passes through two points, you can use the slope-intercept form of a linear equation: y = mx + b, where m represents the slope of the line and b represents the y-intercept.

Step 1: Calculate the slope (m) using the formula:
m = (y2 - y1) / (x2 - x1)
Let's use the two given points (0,4) and (7,10):
m = (10 - 4) / (7 - 0)
= 6 / 7

Step 2: Use one of the given points and the calculated slope to find the y-intercept (b). Let's use the point (0,4):
y = mx + b
4 = (6/7) * 0 + b
4 = b

Step 3: Substitute the slope (m) and y-intercept (b) into the equation y = mx + b.
The equation of the line passing through the points (0,4) and (7,10) is:
y = (6/7) * x + 4

Therefore, the equation of the line is y = (6/7) * x + 4.