Physics

A 50 g ball of clay traveling at speed v0 hits and sticks to a 1.0 kg block sitting at rest on a frictionless surface.

A) What is the speed of the block after the collision?

B) What percentage of the ball's initial energy is "lost"?

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asked by Trevor
  1. .050 Vo = 1.050 v
    so
    v = .0476 Vo

    initial Ke = (1/2)(.05)Vo^2
    final Ke = (1/2)(1.05)v^2

    100 (.05 Vo^2 - 1.05 v^2) /.05 Vo^2

    100 (.05 Vo^2 - .00238 Vo^2)/.05 Vo^2

    = 95.2 % of initial energy is lost

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    posted by Damon

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