Complete and balance the reaction of

A) (CH3)2NH(aq)+CH3COOH(aq)→

B) CH3CH2NH2(aq)+HBr(aq)→

C) CH3NH2(aq)+HCOOH(aq)→

To complete and balance a chemical reaction, we need to ensure that the number of atoms on both sides of the equation is equal and that the charges are balanced.

A) (CH3)2NH(aq) + CH3COOH(aq) → ?

To balance this equation, we need to ensure that the number of carbon, hydrogen, and nitrogen atoms is equal on both sides.

Looking at the reactants, we have:
1 carbon atom in CH3COOH
2 carbon atoms in (CH3)2NH
So we need to have a coefficient of 2 in front of CH3COOH.

To balance the carbon atoms, we have:
3 hydrogen atoms in CH3COOH
6 hydrogen atoms in (CH3)2NH
So we need to have a coefficient of 2 in front of CH3COOH.

Lastly, we have:
1 nitrogen atom in (CH3)2NH
0 nitrogen atoms in CH3COOH
To balance the nitrogen atoms, we need to have a coefficient of 1 in front of (CH3)2NH.

The balanced reaction is:
2(CH3)2NH(aq) + 2CH3COOH(aq) → (CH3)2N-CO-CH3(aq) + 2H2O(l)

B) CH3CH2NH2(aq) + HBr(aq) → ?

To balance this equation, we need to ensure that the number of carbon, hydrogen, and nitrogen atoms is equal on both sides.

Starting with the reactants, we have:
2 carbon atoms in CH3CH2NH2
1 carbon atom in HBr
To balance the carbon atoms, we need to have a coefficient of 2 in front of HBr.

Next, looking at the hydrogen atoms, we have:
7 hydrogen atoms in CH3CH2NH2
1 hydrogen atom in HBr
So we need to have a coefficient of 7 in front of HBr.

Lastly, we have:
1 nitrogen atom in CH3CH2NH2
0 nitrogen atoms in HBr
To balance the nitrogen atoms, we need to have a coefficient of 1 in front of HBr.

The balanced reaction is:
2CH3CH2NH2(aq) + 7HBr(aq) → (CH3CH2NH2)2Br(aq) + 2H2O(l)

C) CH3NH2(aq) + HCOOH(aq) → ?

To balance this equation, we need to ensure that the number of carbon, hydrogen, and nitrogen atoms is equal on both sides.

Starting with the reactants, we have:
2 carbon atoms in HCOOH
1 carbon atom in CH3NH2
To balance the carbon atoms, we need to have a coefficient of 2 in front of CH3NH2.

Next, looking at the hydrogen atoms, we have:
2 hydrogen atoms in HCOOH
7 hydrogen atoms in CH3NH2
So we need to have a coefficient of 7 in front of HCOOH.

Lastly:
0 nitrogen atoms in HCOOH
1 nitrogen atom in CH3NH2
To balance the nitrogen atoms, we need to have a coefficient of 2 in front of CH3NH2.

The balanced reaction is:
2CH3NH2(aq) + 7HCOOH(aq) → (CH3NH2)2CO(aq) + 5H2O(l)