Chemistry. HELP.

You react 25.0 liters of oxygen gas at STP with 50.0 ml of ethanol liquid. Ethanol has a density of 0.789 g/ml.

The excess reactant is:
-C2H5OH
-O2
-CO2
-H2O
-C
-H2
-CO

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  1. I do these the long way.
    mols O2 = 25/22.4 = estimated 1+.
    g ethanol = m = vd = 50.0 x 0.789 = estimated 40 g, then
    mol = g/molar mass = estd 40/46 = estd 0.9

    C2H5OH + 3O2 ==> 2CO2 + 3H2O
    Convert mols O2 to mols CO2 using the coefficients in the balanced equation.
    1+mol O2 x (2 mols CO2/3 mol O2) = estd 0.7
    Convert mols ethanol to mols CO2.
    0.9 x (2 mols CO2/1 mol ethanol) = estd 1.8.
    The two values for mols CO2 produced don't agree which means one of them is wrong; in limiting reagent problems the correct answer is ALWAYS the smaller value and the reagent responsible for that is the limiting reagent. Therefore, the limiting reagent is O2 which makes the excess reagent .....?
    You should confirm all of those numbers because I've estimated them but I don't think it will change the answer.

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    posted by DrBob222
  2. ELASTICITY, LIKE YOUR SOCKS (10/10 points)
    The crystal structure of graphite is shown below. Use the figure to answer the following questions.

    Compare the Young's moduli for the directions indicated in the figure. Fill in the blank.

    The modulus along a is _________ that along b

    equal to - correct
    The modulus along a is _________ that along c

    greater than - correct
    The modulus along b is _________ that along c

    greater than - correct
    Which of the following reasons best explain your reasoning when comparing the moduli of b and c?

    The Poisson ratio is greater than 0.3 in graphite.
    The two directions are crystallographically identical
    Fundamental bending and stretching of bonds is different in the two directions
    Van der Waals bonding has a lower bond strength than colavent bonding - correct <--
    Stretching of covalent bonds requires greater force than bending such bonds
    The opportunity to stetch rings in one direction gives one direction a lower modulus

    Which of the following reasons best explain your reasoning when comparing the moduli of a and b?

    Stretching of covalent bonds requires greater force than bending such bonds
    The Poisson ratio is greater than 0.3 in graphite.
    The two directions are crystallographically identical - correct <---
    Fundamental bending and stretching of bonds is different in the two directions
    The opportunity to stetch rings in one direction gives one direction a lower modulus
    Van der Waals bonding has a lower bond strength than colavent bonding

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