physics

A clerk moves a box of cans down an aisle by pulling on a strap attached to the box. The clerk pulls with a force of 173.0 N at an angle of 31° with the horizontal. The box has a mass of 40 kg, and the coefficient of kinetic friction between the box and the floor is 0.45. Find the acceleration of the box.

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  1. Wb = m*g = 40kg * 9.8N/kg = 392 N. =
    Weight of box.

    Fk=u*(Wb-F*sin31)=0.45(392-173*sin31) =
    136.3 N.= Force of kinetic friction.

    Fn=F*CosA-Fk = 173*cos31 - 136.3 = 12 N.
    = Net force.

    a = Fn/m = 12/40 = 0.30 m/s^2.

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    posted by Henry

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