Algebra 1

A line segment has endpoints j ( 2, 4 ) and l ( 6, 8 ). The point k is the midpoint of jl. What is an equation of a line perpendicular to jl and passing through k?

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asked by Jaay
  1. Slope of segment, a
    = (y2-y1)/(x2-x1)
    = (8-4)/(6-2)=1
    Mid-point
    =( (x1+x2)/2, (y1+y2)/2 )
    =( (2+6)/2, (4+8)/2 )
    = M(4,6)

    Slope of line perpendicular to segment,a1
    = -1/a
    = -1/(1)
    =-1

    Equation of perpendicular line:
    (y-y1)=a1(x-x1)
    y-6 = -1(x-4)
    or
    y=-x + 10

    Check that it goes through M
    -4+10=6 ok.

    1. 👍 1
    2. 👎 1
    posted by MathMate
  2. y=-x+10

    1. 👍 2
    2. 👎 2
    posted by Haley
  3. gdxgdx

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    2. 👎 6
    posted by gdx

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