# Algebra 1

A line segment has endpoints j ( 2, 4 ) and l ( 6, 8 ). The point k is the midpoint of jl. What is an equation of a line perpendicular to jl and passing through k?

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3. 👁 1,687
1. Slope of segment, a
= (y2-y1)/(x2-x1)
= (8-4)/(6-2)=1
Mid-point
=( (x1+x2)/2, (y1+y2)/2 )
=( (2+6)/2, (4+8)/2 )
= M(4,6)

Slope of line perpendicular to segment,a1
= -1/a
= -1/(1)
=-1

Equation of perpendicular line:
(y-y1)=a1(x-x1)
y-6 = -1(x-4)
or
y=-x + 10

Check that it goes through M
-4+10=6 ok.

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posted by MathMate
2. y=-x+10

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2. 👎 2
posted by Haley
3. gdxgdx

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2. 👎 6
posted by gdx

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