algbra 2

1. find the vertex of the parabola.
4x=y^2+6y-11

2. find the center and radius of this circle
x^2+y^2-6x+4y-4=0

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  1. I will do the second question first

    x^2+y^2-6x+4y-4=0
    x^2 - 6x + ___ + y^2 + 4y + ___ = 4
    x^2 - 6x + 9 + y^2 + 4y + 4 = 4 + 9 + 4
    (x-3)^2 + (y+2)^2 = 17

    centre is (3,-2) and radius is √17

    by completing the square on the right side of the first equation, then dividing both sides by 4 gives you
    x = .....

    you must realize that this is a horizontal parabola, so be careful to read off the vertex.

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