An object is thrown or fired straight upwards at an initial speed of v_0 ft⁄s will reach height h feet after t seconds, where h and t are related to the formula
Suppose the object is fired straight upwards with an initial speed of 800ft⁄s, What is the initial velocity?
How does it change the equation h=-16t^2+v_0 t?
What is the initial position of the object?
When does the object fall back to the ground?
When does the object reach a height of 6400ft?
When does the object reach a height of 2mi?
How high is the highest point the ball reaches?
Suppose the object is dropped from a height of 288ft, what is v_0?
The equation becomes h=-16t^2+h_0 after (g) Why?
Write an equation which includes 288ft
An object is thrown or fired straight upwards at an initial speed of v_0 ft⁄s will reach height h feet after t seconds, where h and t are related to the formula h=-16t^2-v_0 t Suppose the object is fired straight upwards
A bullet is dropped into a river from a very high bridge. At the same time, another bullet is fired from a gun straight down towards the water. If air resistance is negligible, the acceleration of the bullets just before they
a cannonball is fired horizontally from the top of a cliff. the cannon is at height H=60.0m above ground level , and the ball is fired with initial horizontal speed v_0 .assume acceleration due to gravity to be g=9.80 find d/2 int
A ball is thrown straight up in the air and passes a window 0.30s after being released. It takes 1.5s to go from the window to its maximum height and back down to the window. What was the initial velocity of the ball when it was
A first object is thrown vertically upward with some initial speed and some initial height above the ground. Simultaneously, a second object is thrown straight down with the same initial speed and same initial height above the
A ball is thrown from ground level up in the air at 61m/s. How fast is the ball going 1s after being thrown. This problem wants you to use the formula v = (-1/2)gt^2 + v_0 g=9.8m/s^2 and v_0 = 61m/s so v = (-1/2)g*(1s)^2 + 61m/s