A shop owner bought 30 folders and some journal. He paid @82.50 for the folders. Each journal cost 10 times as much as a folder. What was the cost of each journal?

F+J=30

30F=82.50
solve for F, folder cost.
Then J, cost of Journal=10xF

To find the cost of each journal, we can start by calculating the cost of the folders.

Let's assume the cost of each folder is "x." Since the shop owner bought 30 folders, the total cost of the folders would be 30 * x.

According to the given information, the shop owner paid $82.50 for the folders, so we can set up the equation:

30 * x = $82.50

Now let's solve for x by dividing both sides of the equation by 30:

x = $82.50 / 30
x = $2.75

Therefore, each folder costs $2.75.

The problem also states that each journal costs 10 times as much as a folder. We can find the cost of each journal by multiplying the cost of a folder by 10:

Cost of each journal = Cost of each folder * 10
Cost of each journal = $2.75 * 10
Cost of each journal = $27.50

Therefore, the cost of each journal is $27.50.