hectorr

Solve the fractional equation check yur solution

3[2x-(x+7)]=5(x-3)

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  1. Why do you call this a fractional equation ?
    I see no fraction in the equation.

    3[2x-(x+7)]=5(x-3)
    3[x-7] = 5x - 15
    3x - 21 = 5x - 15
    -2x = 6
    x = -3

    check: if x = -3
    LS = [3(-6 - 4]
    = 3[-10]
    = -30
    RS = 5(-6) = -30
    = LS

    my solution is correct.

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    posted by Reiny

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