Complete and balance the following


(CH3)2NH(aq)+CH3COOH(aq)→

CH3CH2NH2(aq)+HBr(aq)→

CH3NH2(aq)+HCOOH(aq)→

The first is a condensation reaction not an acid base like other answers have suggested

To complete and balance the given chemical equations, we need to ensure that the same number of atoms of each element exist on both sides of the equation. Let's balance each equation one by one.

1. (CH3)2NH(aq) + CH3COOH(aq) → CH3CH2NH2(aq) + H2O(l)
In this equation, we have two carbon (C) atoms, eight hydrogen (H) atoms, two nitrogen (N) atoms, and two oxygen (O) atoms on the left side. On the right side, there are three carbon (C) atoms, seven hydrogen (H) atoms, two nitrogen (N) atoms, and two oxygen (O) atoms.

To balance the number of atoms, we can add a coefficient in front of each compound. The balanced equation is:

2(CH3)2NH(aq) + CH3COOH(aq) → CH3CH2NH2(aq) + H2O(l)

2. CH3CH2NH2(aq) + HBr(aq) → CH3CH2NH3Br(aq)
In this equation, there are 2 carbon (C) atoms, 8 hydrogen (H) atoms, 1 nitrogen (N) atom, and 1 bromine (Br) atom on both sides. Hence, the equation is already balanced.

3. CH3NH2(aq) + HCOOH(aq) → CH3NH3+(aq) + HCOO-(aq)
In this equation, we have 1 carbon (C) atom, 5 hydrogen (H) atoms, 2 nitrogen (N) atoms, and 2 oxygen (O) atoms on the left side. On the right side, there are 1 carbon (C) atom, 6 hydrogen (H) atoms, 3 nitrogen (N) atoms, and 2 oxygen (O) atoms.

To balance the number of atoms, we can add coefficients:
2CH3NH2(aq) + 2HCOOH(aq) → 2CH3NH3+(aq) + 2HCOO-(aq)

Thus, the balanced chemical equations are:
1. 2(CH3)2NH(aq) + CH3COOH(aq) → CH3CH2NH2(aq) + H2O(l)
2. CH3CH2NH2(aq) + HBr(aq) → CH3CH2NH3Br(aq)
3. 2CH3NH2(aq) + 2HCOOH(aq) → 2CH3NH3+(aq) + 2HCOO-(aq)