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According to the following thermochemical reaction, how much energy is involved in the reaction of 18.5 g of NaHCO3? Is the reaction endothermic or exothermic according to how the thermochemical equation is written?

2NaHCO3(s) + 129 kJ → Na2CO3(s) + H2O(l) + CO2(g)

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asked by Jenna
  1. You have to add heat so endothermic

    129 J per 2 mol

    1 mol = 23 + 1 + 12 + 48 = 84 grams
    2 mol = 168 grams
    we only have 18.5 grams so
    (18.5/168)129 = 14.2 Joules

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    posted by Damon
  2. I think Damon made a typo. That is kJ and not J.

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  3. Thanks for catching that !!!

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    posted by Damon

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