Math

A model rocket is launched from a roof of a building. Its path is described by the relationship h=-5t*2+35t+10, where h is the height in metres and t is the time in seconds. How tall is the building? What is the maximum height that the rocket will reach? When will the rocket be 40 metres above the ground? Explain your answer.

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asked by Lorrie
  1. The building is 10 metres tall.
    h=-5t^2+35t+10
    =-5(t^2-7t-2)
    =-5(t^2-7t+12.25-12.25)+10
    =-5(t^2-7t+12.25)+61.25+10
    = -5(t^2-7t+12.25)+71.25
    =-5(t-3.5)^2 + 71.25
    So at 3.5 seconds the maximum height is 71.25 metres high.
    Is this correct?

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    posted by Lorrie
  2. Are the first 2 parts correct?
    Hint please on the third part? I think I need the velocity? How to calculate?

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    posted by Lorrie

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