The equation of a circle is (x−4)^2+ (y+2)^2=16.
B) Find the radius of the circle with the given equation.
Can somone give me step by step explanations?
Thank you in advance!
review the description of a circle with center at (h,k) and radius r:
(x-h)^2 + (y-k)^2 = r^2
Thank you Steve.
To find the radius of a circle, we can use the equation of the circle in the form "(x-a)^2 + (y-b)^2 = r^2", where (a, b) is the center of the circle and r is the radius.
In this case, the equation of the circle is "(x-4)^2 + (y+2)^2 = 16". By comparing this equation with the standard form above, we can see that the center of the circle is at the point (4, -2).
To find the radius, we simply need to take the square root of the number on the right side of the equation. In this case, the radius is the square root of 16, which is 4.
So, the radius of this circle is 4.