What is the theoretical probability of rolling a sum of 6 on one roll of two standard number cubes?
A. 1/9
B. 5/36
C. 1/12
D. 1/6
B
P(6) = 5 / 36
ways to roll two dice: (6 * 6) = 36
ways to roll 6: (1, 5), (5, 1), (2, 4), (4, 2), (3, 3)
one at a time
oops nvmd that's for rolling a sum of 10
5/36
5/36
Yes, that's correct!
To determine the theoretical probability of rolling a sum of 6 on one roll of two standard number cubes, we need to first count the number of ways we can get a sum of 6, and then divide it by the total number of possible outcomes.
Let's start by listing all the possible outcomes when rolling two standard number cubes (also known as dice). Each die has six faces numbered 1 to 6.
To get a sum of 6, we have the following combinations:
- (1, 5) or (5, 1)
- (2, 4) or (4, 2)
- (3, 3)
- (4, 2) or (2, 4)
- (5, 1) or (1, 5)
- (6, 6)
So, there are a total of 5 possible ways to get a sum of 6.
Now, let's calculate the total number of possible outcomes when rolling two dice. Since each die has 6 faces, the total number of outcomes is 6 x 6 = 36.
To find the theoretical probability, we divide the number of desired outcomes (getting a sum of 6) by the total number of possible outcomes.
Probability = Number of desired outcomes / Total number of possible outcomes
Probability = 5 / 36
So, the theoretical probability of rolling a sum of 6 on one roll of two standard number cubes is 5/36.
Therefore, the correct option is B. 5/36.