Evaluate the express. nCr
(9 over 6)(6 over 4)(3 over 1)
n 9 6 3
r 6 4 1
I came up with,
[10 over 6!(10-6] [6 over 4(4-2!)
[3 over 1!(1-1)!] from there I so sorry I don't know where to go.
thank you
not sure just what you want.
9C6 = 9C3 = 9*8*7/1*2*3 = 84
6C4 = 6C2 = 6*5/1*2 = 15
3C1 = 3/1 = 3
More formally,
9C6 = 9! / (9-6)!6!
6C4 = 6! / (6-4)!4!
3C1 = 3! / (3-1)!1!
I have know what numbers I will have to multiple
9 6 3
6 4 1 =
I think you are referring to one of the alternate ways to represent a combination
see:
http://laurashears.info/math122/unit5/notation/
Steve found the value of each of your combinations, so just multiply them
84*15*3 = .......
Here is a combinations and permutations calculator
to get permutations, the "Is order important" box should be YES
to get combinations the is order important box is NO
http://www.mathsisfun.com/combinatorics/combinations-permutations-calculator.html
Here you are doing combinations, nCr so the box should be NO
To evaluate the expression nCr, where n and r are positive integers, we use the formula for combinations:
nCr = n! / (r!(n-r)!)
Let's calculate each part step-by-step:
1. Calculate 9C6:
9C6 = 9! / (6!(9-6)!)
= 9! / (6! * 3!)
= (9 * 8 * 7 * 6!) / (6! * 3 * 2 * 1)
= (9 * 8 * 7) / (3 * 2 * 1)
= 84
2. Calculate 6C4:
6C4 = 6! / (4!(6-4)!)
= 6! / (4! * 2!)
= (6 * 5 * 4!) / (4! * 2 * 1)
= (6 * 5) / (2 * 1)
= 15
3. Calculate 3C1:
3C1 = 3! / (1!(3-1)!)
= 3! / (1! * 2!)
= (3 * 2 * 1!) / (1! * 2 * 1)
= 3
Now, let's multiply these results together:
(9C6) * (6C4) * (3C1) = 84 * 15 * 3
= 3780
Therefore, the value of (9 over 6)(6 over 4)(3 over 1) is 3780.