If the solubility of a gas in water is 1.22 g/L at 2.75 atm, what is its solubility (in g/L) at 1.0 atm?
A. 0.44 g/L
B. 3.97 g/L
C. 2.25 g/L
D. 3.36 g/L
I think the answer is C.. i did 2.75 x 1.0 = 2.75 / 1.22 = 2.25 but people say the answer is A... why?
i think the answer is c...i did 2.75 x 1.0 =
The answer is A. Gas solubility is proportional to pressure.
solubility=1/2.75 * 1.22
that makes sense thank u!
To determine the solubility (in g/L) of a gas at different pressures, you can use the following equation:
(solubility at one pressure) / (solubility at another pressure) = (pressure1) / (pressure2)
In this case, you want to find the solubility at 1.0 atm when the solubility at 2.75 atm is known to be 1.22 g/L.
Let's plug in the values into the equation:
(solubility at 2.75 atm) / (solubility at 1.0 atm) = (2.75 atm) / (1.0 atm)
Now, rearrange the equation to solve for the solubility at 1.0 atm:
(solubility at 1.0 atm) = (solubility at 2.75 atm) / (2.75 atm) * (1.0 atm)
(solubility at 1.0 atm) = 1.22 g/L / 2.75 * 1.0
(solubility at 1.0 atm) = 0.44 g/L
Therefore, the correct answer is A. 0.44 g/L.
To solve this problem, you can use the principles of Henry's Law, which states that the solubility of a gas in a liquid is directly proportional to the partial pressure of the gas above the liquid.
In this case, let's assume the solubility of the gas at 1.0 atm is x g/L. According to Henry's Law, we can set up the following proportion:
1.22 g/L / 2.75 atm = x g/L / 1.0 atm
To solve for x, we can cross-multiply and divide:
1.22 g/L * 1.0 atm = 2.75 atm * x g/L
1.22 = 2.75x
x = 1.22 / 2.75
x = 0.444 g/L
Therefore, the correct answer is A. The solubility of the gas at 1.0 atm is approximately 0.444 g/L.