WHICH IS LIMITING REAGENT IN FOLLOEING REACTION 3Mg +N2 =Mg3N2
Hard to say. If there's an excess of Mg, then the N2 is the limiting reagent.
If there's plenty of N2 around, then the Mg limits the reaction.
3Mg
To determine the limiting reagent in a reaction, you need to compare the stoichiometry of the reactants involved. In this case, the reaction is:
3Mg + N2 -> Mg3N2
The stoichiometric ratio shows that for every 3 moles of Mg reacting, 1 mole of N2 is needed to form 1 mole of Mg3N2.
To find the limiting reagent, you need to compare the number of moles of each reactant to see which one is present in the least amount. Whichever reactant is present in the least amount is the limiting reagent, as it will be completely consumed in the reaction, limiting the amount of product that can be formed.
Let's say you have the following quantities of reactants:
- 4 moles of Mg
- 2 moles of N2
To determine the limiting reagent, you can use the stoichiometry of the reaction:
For Mg: 4 moles of Mg * (1 mole of N2 / 3 moles of Mg) = 4/3 moles of N2
For N2: 2 moles of N2 * (3 moles of Mg / 1 mole of N2) = 6 moles of Mg
From the calculations, we can see that there is an excess of N2 because you would need 6 moles of Mg to react with all of the N2, but you only have 4 moles available. On the other hand, you have enough Mg to react with all of the N2.
Therefore, the limiting reagent in this reaction is Mg, as it will be completely consumed before all the N2 is used up.