The solubityof a compound in water is 6.8g/100ml at 0degreesC and 0.33g/100ml at 25degreesC.calculate the amount of water required to crystallize 10g of the compound.If the compound is collected at 25degreesC what is the maximum possible yield present?

Difference in solubility = 6.8-0.33 g

=6.47 g/100 ml.

10 g / ? ml. (of solution)

To calculate the amount of water required to crystallize the compound, we need to use the solubility data provided.

At 0 degrees Celsius, the solubility of the compound in water is 6.8 g/100 ml. This means that 100 ml of water can dissolve 6.8 g of the compound.

At 25 degrees Celsius, the solubility of the compound in water is 0.33 g/100 ml. This means that 100 ml of water can dissolve 0.33 g of the compound.

To determine the amount of water required to crystallize 10 g of the compound, we can set up a proportion based on the solubility data at each temperature:

(6.8 g / 100 ml) = (10 g / x ml)

Solving for x, we get:

x = (10 g * 100 ml) / 6.8 g ≈ 147 ml

Therefore, approximately 147 ml of water would be required to crystallize 10 g of the compound at 0 degrees Celsius.

Now let's calculate the maximum possible yield of the compound when collected at 25 degrees Celsius.

If the solubility of the compound in water at 25 degrees Celsius is 0.33 g/100 ml, it means that 100 ml of water can dissolve 0.33 g of the compound.

If we have 147 ml of water (calculated above) to crystallize the compound, we can use this information to find the maximum possible yield:

Maximum possible yield = (0.33 g / 100 ml) * 147 ml

Maximum possible yield = 0.4851 g

Therefore, the maximum possible yield of the compound, when collected at 25 degrees Celsius, would be approximately 0.4851 grams.