# physics

a man walks 8km North and then 5km in a. direction 60degrees. find its distance from his starting point

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1. Use the component method to break down each vector into x,y components.
8km North = <0,8>
5km at 60° = <5cos60°,5sin60°>
Assuming angle is in Cartesian plane (counterclockwise from east) and not bearing (clockwise from north).

Add the two vectors and calculate the magnitude of the resultant.

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2. 56

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3. 5km

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posted by dorcas

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