physics

a man walks 8km North and then 5km in a. direction 60degrees. find its distance from his starting point

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  1. Use the component method to break down each vector into x,y components.
    8km North = <0,8>
    5km at 60° = <5cos60°,5sin60°>
    Assuming angle is in Cartesian plane (counterclockwise from east) and not bearing (clockwise from north).

    Add the two vectors and calculate the magnitude of the resultant.

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  2. 56

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  3. 5km

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    posted by dorcas

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