max flipped a pair of coins 60 times. On 24 occasaions, heads appeared on both coins. How is this outcome different from the expected outcome?
It occurred 9 more times than expected.
It occurred 4 more times than expected.
It occurred 6 fewer times than expected
It occurred the expected number of times.
there are four possible outcomes of flipping a pair
h h
h t
t h
t t
so you should get h h
60/4 = 15 times
we got it 24 or 9 more times than expected
Ok sorry. :(
Thank I am really trying really hard to understand. I got other ones I haven't posted here. I just ask for the ones I tried over and over again. Thank you.
I am writing what you wrote Damon in my math note book. Thanks.
Can you delete m questions today?
To determine the expected outcome when flipping a pair of coins, we need to consider the probability of getting heads on both coins.
The probability of getting heads on a single coin flip is 1/2, as there are two equally likely outcomes (heads or tails). When flipping two coins, the outcomes are independent, meaning the probability of both coins showing heads is calculated by multiplying the probabilities of each individual coin showing heads.
So the probability of getting heads on both coins = (1/2) * (1/2) = 1/4.
Next, we need to find the expected outcome by multiplying the probability of getting heads on both coins by the number of times the coins are flipped.
Expected outcome = (probability of getting heads on both coins) * (number of coin flips) = (1/4) * 60 = 15.
Given that heads appeared on both coins 24 times, we can compare this to the expected outcome of 15 to determine the difference:
Difference = actual outcome - expected outcome = 24 - 15 = 9.
Therefore, the correct answer is:
"It occurred 9 more times than expected."