1) The linear function f(x) contains the points (-10, -29) and (-2, 83).

If g(x) = 25x - 50, which statement is true?
A. The functions f(x) and g(x) both have positive slopes. <<<

B. The functions f(x) and g(x) both have negative slopes.

C. The function f(x) has a positive slope, and the function g(x) has a negative slope.

D. The function f(x) has a negative slope, and the function g(x) has a positive slope.

2) A population of caribou in a forest grows at a rate of 2% every year. If there are currently 237 caribou, which function represents the number of caribou in the forest in t years?
A. C(t) = 237(0.98)^t
B. C(t) = 237(1.02)^t <<<<
C. C(t) = (237)(1.02)^t
D. C(t) = 237(0.02)^t

3) Robert is considering purchasing a manufactured home that costs \$77,300. If he expects the home value to decrease 8% each year, which function will show the value of Robert's manufactured home in t years?
A. V(t) = \$83,484t
B. V(t) = \$77,300(-0.92)t
C. V(t) = \$77,300(1.08)t <<<<<<<<
D. V(t) = \$77,300(0.92)t

4) The formula below can be used to find the amount of radioactive material that remains after a certain period of time, where A0 is the initial amount of material, A is the amount of material remaining after t hours, and k is the decay constant.

A = A0(2.71)-kt

If Celeste has 83.3 grams of a radioactive material initially, and it has a decay constant of 0.6, how much of the material, in grams, will remain after 2 hours? Round to the nearest hundredth of a gram, if necessary.
A. 45.8 <<<<<<<<<<<<
B. 11.34
C. 25.18
D. 12.59

1. 👍 0
2. 👎 0
3. 👁 92
1. 3) Robert is considering purchasing a manufactured home that costs \$77,300. If he expects the home value to decrease 8% each year, which function will show the value of Robert's manufactured home in t years?
A. V(t) = \$83,484t
B. V(t) = \$77,300(-0.92)t
C. V(t) = \$77,300(1.08)t <<<<<<<<
D. V(t) = \$77,300(0.92)t

D. V(t) = \$77,300(0.92)t
BUT you mean
D. V(t) = \$77,300(0.92)^t

1. 👍 0
2. 👎 0
posted by Damon
2. Thanks! Are the others correct?

1. 👍 0
2. 👎 0
posted by David
3. 4) The formula below can be used to find the amount of radioactive material that remains after a certain period of time, where A0 is the initial amount of material, A is the amount of material remaining after t hours, and k is the decay constant.

A = A0(2.71)-kt !!!!!!!!
=====================================
AGAIN YOU MEAN
A = AO (2.71)^-kt
=========================
BY 2.71 you mean e
=========================

If Celeste has 83.3 grams of a radioactive material initially, and it has a decay constant of 0.6, how much of the material, in grams, will remain after 2 hours? Round to the nearest hundredth of a gram, if necessary.
A. 45.8 <<<<<<<<<<<<
B. 11.34
C. 25.18
D. 12.59

A = 83.3 e^-(.6*2)
= 83.3 * .3011
= 25.08
so I think C

1. 👍 0
2. 👎 0
posted by Damon
4. Are 1 and 2 correct?

1. 👍 0
2. 👎 0
posted by David

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