The volume of a gas is 150 mL at 240.0 kPa pressure. What will the pressure be when the volume is reduced to 100.0 kPa, assuming the temperature remains constant?
P1V1 = P2V2
To find the pressure when the volume is reduced, we can use Boyle's law, which states that the pressure and volume of a gas are inversely proportional at a constant temperature.
Boyle's law equation is:
P1 * V1 = P2 * V2
where P1 is the initial pressure, V1 is the initial volume, P2 is the final pressure, and V2 is the final volume.
In this case, we are given:
P1 = 240.0 kPa
V1 = 150 mL
V2 = V1 (since the volume is reduced to a given value of 100.0 mL)
We need to find P2.
Now, we can substitute the given values into the equation:
P1 * V1 = P2 * V2
240.0 kPa * 150 mL = P2 * 100 mL
To solve for P2, we first convert the volumes to the same unit, such as mL:
240.0 kPa * 150 mL = P2 * 100 mL
36,000 kPa * mL = P2 * 100 mL
Now, we can cancel out the mL:
36,000 kPa = P2 * 100
Next, solve for P2 by dividing both sides of the equation by 100:
36,000 kPa / 100 = P2
P2 = 360 kPa
Therefore, the pressure when the volume is reduced to 100.0 mL would be 360.0 kPa.